Answer:
Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.
Answer:
A. 26 1/2
Step-by-step explanation:
change denominator so they can be the same
3/4*3 = 9/12
1/3*4 = 4/12
Add the whole numbers : 10 +15=25
9/12+4/12= 13/12 so 1 1/12
26 1/12
Answer:
#9
I can't write out the whole proof here.
it bisects, so we know BCA is congruent to DCA
abc being congruent to adc is given
AC = AC because it is a singular side
AAS
then the lines are congruent by CPCTC
