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sveticcg [70]
3 years ago
14

Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.

Mathematics
1 answer:
melomori [17]3 years ago
4 0

Answer:

part 1: A

part 2: A

Step-by-step explanation:

Part 1:

I think it is A (c ≤ 56), since it should be less than or equal to, due to it describing how many are left : 56 and less are left

B can't be right even though it is less than or equal to, since it says that -56 cans are left to collect: nonsense

Part 2:

A represents c ≤ 56

C represents c ≤ –56

B represents c ≥ 56

D represents c ≥ –56

thus, answer is A

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F(x) = 5x2 − 70x + 258. Complete the square.
astraxan [27]
5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done
7 0
4 years ago
Multiplication mod 29 by 30 is equivalent to standard multiplication by ___
arsen [322]
The awnser will be 870.
4 0
3 years ago
Please help! Will give brainliest!:)
Mrrafil [7]

Answer:

Ex1: If $1000 is invested now with simple interest of 8% per year. Find the new amount after two years. P = $1000, t = 2 years, r = 0.08.

Step-by-step explanation:

hope this helps

8 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
HELP PLEASE! Im struggling
kondaur [170]

Answer:

c. \dfrac{2}{3}

Step-by-step explanation:

Let the common ratio be r.

a_2 = \dfrac{2}{5}

a_3 = \dfrac{2}{5}r

a_4 = \dfrac{2}{5}r^2

a_5 = \dfrac{2}{5}r^3

We are told that a_5 = \dfrac{16}{135}.

\dfrac{2}{5}r^3 = \dfrac{16}{135}

\dfrac{5}{2} \times \dfrac{2}{5}r^3 = \dfrac{5}{2} \times \dfrac{16}{135}

r^3 = \dfrac{8}{27}

r = \sqrt[3]{\dfrac{8}{27}}

r = \dfrac{2}{3}

Answer: c. \dfrac{2}{3}

6 0
3 years ago
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