A) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
<span>I choose one senior: r = 1
</span>
nCr = n! / (r! (n - r)!)
5C1 = 5! / (1! (5 - 1)!)
= (5 * 4 * 3 * 2 * 1) / (1 * 4!)
= 120 / (4 * 3 * 2 * 1)
= 120 / 24
= 5
b) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose two seniors: r = 2
nCr = n! / (r! (n - r)!)
5C2 = 5! / (2! (5 - 2)!)
= (5 * 4 * 3 * 2 * 1) / ((2 * 1) * 3!)
= 120 / (2 * (3 * 2 * 1))
= 120 / (2 * 6)
= 120 / 12
= 10
c) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose three seniors: r = 3
nCr = n! / (r! (n - r)!)
5C3 = 5! / (3! (5 - 3)!)
= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * 2!)
= 120 / (6 * (2 * 1))
= 120 / (6 * 2)
= 120 / 12
= 10
d) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose four seniors: r = 4
nCr = n! / (r! (n - r)!)
5C4 = 5! / (4! (5 - 4)!)
= (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1!)
= 120 / (24 * 1)
= 120 / 24
= 5
e) The answer is 1.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose five seniors: r = 5
nCr = n! / (r! (n - r)!)
5C5 = 5! / (5! (5 - 5)!)
= (5 * 4 * 3 * 2 * 1) / ((5 * 4 * 3 * 2 * 1) * 1!)
= 120 / (120 * 1)
= 120 / 120
= 1
9-6i is the answer, combine like terms
Answer
x = 2 + √15/11, 2 - √15/11
Decimal Form:
x = 0.53390757
x = -0.17027121
Step-by-step explanation:
^^
The answer for # 1) B 1/3
is #2 not the same quesztion tho ?
Congruent= the same shape and size.
area of the rectangle before it is divided=8*(area congruent rectangle)
area of the rectangle before it is dividide=8*(5 cm²)=40 cm²
Area of the rectangle before it is dividide=40 cm²
