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arsen [322]
3 years ago
5

Please answer this question for me and remember its witch of the following would NOT contain that point.

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

Your answer is y=1/2x+8

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I WILL GIVE U BRAINLIEST, NO LINKS. ITS JUST 1 QUESTION
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It’s the first one :)
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Anybody who is good with word problems and (who has done these before) plz help thx!!! :DD
vovikov84 [41]

1. \frac{x}{15}  = 3

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Help! Select all of the potential solution(s) of the equation 2log5x = log54.
Nastasia [14]

Answer:

  • x = 2

Step-by-step explanation:

  • 2 log₅ x = log₅ 4
  • 2 log₅ x = log₅ 2²
  • 2 log₅ x = 2 log₅ 2
  • log₅ x = log₅ 2
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7 0
3 years ago
What is the horizontal asymptote of the function f(x)= -2x/x+1
daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = -\frac{2}{1} = -2

8 0
3 years ago
The length of a rectangle is eight more than twice its width. The perimeter is 96 feet. Find the dimensions of the rectangle
Debora [2.8K]

Answer:

The width  of the rectangle is 14'8",  and the length is 33'4"

Step-by-step explanation:

We're given two pieces of information:

The length is eight more than twice the width:

l = 2w + 4

The perimeter is 96 feet:

p = 96

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

p = 2l + 2w

We can solve for w by plugging the other two values into the last:

p = 2w + 2l\\96 = 2w + 2(2w + 4)\\96 = 2w + 4w + 8\\88 = 6w\\3w = 44\\w = \frac{44}{3}\\w = 14\frac{2}{3}

Now we can find the length by plugging w into the first equation:

l = 2w + 4\\l = 2(14\frac{2}{3}) + 4\\l = 29\frac{1}{3} + 4\\l = 33\frac{1}{3}

One third of  a foot is four inches, so the width is 14'8" and the length is 33'4"

To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

p = 2l + 2w\\p = 2(33\frac{1}{3}) + 2(14\frac{2}{3})\\p = 66\frac{2}{3} + 29\frac{1}{3}\\p = 96

So we know our answer's correct

8 0
2 years ago
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