Given the equation:
You know that the radioactive substance has this half-life (in years)
And:
Therefore, you can rewrite the equation in this form in order to find "k":
Solve for "k":
Answer:
it looks like an acute angle
13g+13 sorry if this is wrong
Answer:
52
Step-by-step explanation:
ITS 52
Answer: D,(11,61,62)
Step-by-step explanation:28,45,53
53²=28²+45²
2,809= 784+2,025
= 2,809
53²=2,809
(28,45,53) is a Pythagorean triple
16,63,65
65²=16²+63²
4225=256+3969
= 4225
65²=4225
(16,63,65) is a Pythagorean triple
13,84,85
85²=13²+84²
7225=169+7056
=7225
85²=7225
(13,84,85) is a Pythagorean triple
11,61,62
62²=11²+61²
3,844=121+3,721
=3,842
62²=3,844
(11,61,62) is not a Pythagorean triple
