Solution in the attachment.
![\det\left[\begin{array}{ccc}4&2&-3\\5&-6&1\\0&2&-1\end{array}\right]=4\cdot\left|\begin{array}{ccc}-6&1\\2&-1\end{array}\right|-2\cdot\left|\begin{array}{ccc}5&1\\0&-1\end{array}\right|-3\cdot\left|\begin{array}{ccc}5&-6\\0&2\end{array}\right|](https://tex.z-dn.net/?f=%20%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%26-3%5C%5C5%26-6%261%5C%5C0%262%26-1%5Cend%7Barray%7D%5Cright%5D%3D4%5Ccdot%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D-6%261%5C%5C2%26-1%5Cend%7Barray%7D%5Cright%7C-2%5Ccdot%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D5%261%5C%5C0%26-1%5Cend%7Barray%7D%5Cright%7C-3%5Ccdot%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D5%26-6%5C%5C0%262%5Cend%7Barray%7D%5Cright%7C%20)

The given angles 3 and 4 shares a common arm, therefore the angles are known as Adjacant Angles
Do you need the steps? g=14
Answer:
[-1, infinity)
Step-by-step explanation:
I must assume that you meant y = √(x - 5) - 1.
The range of the square root function is [0, infinity.
If 1 is subtracted from the square root function, the range of the resulting function is [-1, infinity).
Its B trust i took the test and got it right