Vertex form of a parabola
<span>y = a (x - h)^2 + k </span>
<span>where (h, k) is the vertex </span>
Substituting the values of h and k.
we get,
<span>y = a(x + 4)^2 + 2 </span>
<span>substituting in the point (0, -30) for x and y
</span><span>-30 = a (0 + 4)^2 + 2
</span>solve for a,
<span>-30 = 16 a + 2 </span>
<span>-32 = 16 a </span>
<span>-2 = a </span>
<span>y = -2(x + 4)^2 + 2 </span>
<span>Put y = 0 </span>
<span>-2 x^2 - 16 x - 30 = 0 </span>
<span>-2(x^2 + 8 x + 15) = 0 </span>
<span>x^2 + 8 x + 15 = 0 </span>
<span>(x + 3)(x + 5) = 0 </span>
<span>x = -3
x = -5</span>
Is there a specific question?
Pemdas is usually the general order to solving exponential equations.
(P) Parenthesis, as in simplify what is inside a parenthesis first.
(E) Exponents
(M) Multiplication
(D) Division
(A) Addition
(S) Subtraction, Subtraction would occur last.
:V
Answer:
x=12
Step-by-step explanation:
The right side is a right triangle
The base is 1/2 of the bottom or 5
The height is x and the hypotenuse is 13
We can use the Pythagorean theorem
a^2 +b^2 = c^2
5^2 +x^2=13^2
25+x^2 = 169
Subtract 25 from each side
25-25+x^2 = 169-26
x^2 =144
Take the square root of each side
sqrt(x^2) = sqrt(144)
x= 12
The third one 02 2/5 is the answer
