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Anvisha [2.4K]
3 years ago
13

NEED ASAP URGENT

Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Given:

The figure of two triangles.

To find:

The similarity statement for the given triangles.

Solution:

The corresponding sides of similar triangles are proportional.

In the given triangles,

\dfrac{XY}{AB}=\dfrac{6}{12}

\dfrac{XY}{AB}=0.5

Similarly,

\dfrac{YZ}{BC}=\dfrac{3}{6}

\dfrac{YZ}{BC}=0.5

And,

\dfrac{XZ}{AC}=\dfrac{7}{14}

\dfrac{XZ}{AC}=0.5

Since \dfrac{XY}{AB}=\dfrac{YZ}{BC}=\dfrac{XZ}{AC}, therefore

\Delta XYZ\sim \Delta ABC

It can be written as:

\Delta ZYX\sim \Delta CBA

Therefore, the correct option is A.

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Which of the following is the difference of two squares?
JulijaS [17]

Step-by-step explanation:

  • ATTACHED IS THE SOLUTION!

8 0
2 years ago
Cuánto es (-12) - 21 = <br>Explicación del pq da a ese resultado, por favor.​
Gelneren [198K]

Answer:

the answer is -33 srry couldn't explain :(

7 0
3 years ago
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An ice cream shop sells 6 different flavors, 4 toppings, and 3 types of cones. How many different combinations of two different
Bas_tet [7]

Answer:

360 combinations

Step-by-step explanation:

To calculate the number of different combinations of 2 different flavors, 1 topping, and 1 cone, we are going to use the rule of multiplication as:

<u>               6          </u>* <u>        5             </u> * <u>            4           </u>* <u>          3             </u>= 360

       1st flavor           2nd flavor              topping              cone

Because first, we have 6 possible options for the flavor, then we only have 5 possible options for the 2nd flavor. Then, we have 4 options for the topping and finally, we have 3 options for the cone.

It means that there are 360 different combinations of two different flavors, one topping, and one cone are possible

6 0
3 years ago
Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(
MAVERICK [17]

Answer:

If you center the series at x=1

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

Step-by-step explanation:

From the information given we know that

f(x) = e^{2x^2}

f'(x) = 4x e^{2x^2}   (This comes from the chain rule )

f^{(2)}(x) = 4e^{2x^2} (4x^2+1)   (This comes from the chain rule and the product rule)

f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)  (This comes from the chain rule and the product rule)

If you center the series at x=1  then

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

3 0
3 years ago
Problem A park has a large circle painted in the middle of the playground area. The circle is divided into 444 equal sections, a
Vladimir79 [104]

Answer:

25\pi\ m^2

Step-by-step explanation:

Given that:

A large circle in the park has its middle part painted.

The circle is divided in 4 equal parts.

Radius of the circle = 10 meters

To find:

Area of each section of the circle, A = ?

Solution:

Here, we need to find the area of the bigger circle first and then need to divide it into 4 equal parts to find out the answer.

First of all, let us have a look at the formula for area of a circle with given radius r:

Area = \pi r^2

Here, r = 10 m

Putting the value in the above formula, we get:

So, area = \pi 10^2 = 100\pi\ m^2

Now, there are 4 equal parts of the circle, therefore area of each section will be equal.

Area of each section of the circle:

\dfrac{100\pi}{4} = \bold{25 \pi}\ m^2

7 0
3 years ago
Read 2 more answers
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