Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Gh is a half of DF because it is a midline
2(3x-4)=9x-59
6x-8=9x-59
3x=51
X=17
Answer:
3 < c < 9
Step-by-step explanation:
The length of a side of a triangle cannot be negative. This eliminates the first and last options.
The addition of two sides of a triangle must be greater than the third side. In this case:
3 + 6 = 9 > c
So, the second option is correct. The third option is not correct, because, for example, c = 8 is possible
Answer:
It would be 5000
Step-by-step explanation:
It would be 500 b/c the number is a greater number that is 4802 and it is closer to 5000 than 4000
Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one