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2 years ago

Write a polynomial of degree 3 that satisfies each of the given conditions.

Mathematics

1 answer:

shutvik [7]2 years ago

5 0

Answer:

https://www.jacksonsd.org/cms/lib/NJ01912744/Centricity/Domain/504/BI%207-8.pdf

Step-by-step explanation:

the link to help you with the answers

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The ratio of pens to pencils that Katy has on his desk is 6:5. If Katy has 15 pencils on his desk then how many pens does he hav

polet [3.4K]

Answer:

Step-by-step explanation:

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2 years ago

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A fraction reduces to 36. If its denominator is 6x^5 what is its numerator?

trapecia [35]

Answer:

Your answer will be 6^3x^5

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2 years ago

Find the product of 20x9x5. Tell which property is used.

Likurg_2 [28]

The answer is 900 because 20×9=180 and just multiply 180×5 and that equals 900.

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2 years ago

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Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

4 0

2 years ago

Write the sum as a product of two factors.

Elena-2011 [213]

A) 81 and 48 have a common factor of 3:
81w+48= 3(27w+16)

b) 10 and 25 have a common factor of 5:
10-25t=5(2-5t)

c) 12, 16 and 8 have common factors of 4:
12a+16b+8=4(3a+4b+2)

Hope this helps :)

4 0

2 years ago