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3 years ago

What is the value of ?

Mathematics

2 answers:

kvasek [131]3 years ago

8 0

It's D. 125 cubed USE A CALCULATOR

azamat3 years ago

4 0

Sure! So this is ready as "the cube root of 125". This basically means, "what number cubed can get me 125?"
Let's go through our options.
We can rule out D, as D cubed would be unreasonably big.
We can also rule out C, because 375 cubed is easily over 10000, you know this even if you haven't computed it all, just compute the 300 cubed.
We can rule out B, too. 41 squared is already over 125, therefore it can't be the answer.
Therefore our answer is A, 5. We can check that by cubing 5, and that indeed gets us 125.
Hope this helps!

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A cube has edges measuring 5 inches. Find the surface area of the cube.

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It will be C. Hope this helps! Mark brainly please!

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3 years ago

What is 5*5*5*5*5*5*5 in exponential notation form?

slamgirl [31]

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Step-by-step explanation:

5*5*5*5*5*5*5

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3 years ago

Read 2 more answers

What's -1 80/99 in decimal form

Daniel [21]

Answer: 1.80

Step-by-step explanation:

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3 years ago

Maths!

Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

X $X-\bar X$ $(X-\bar X)^{2}$

5 5 - 8 = -3 9

8 8 - 8 = 0 0

10 10 - 8 = 2 4

9 9 - 8 = 1 1

6 6 - 8 = -2 4

Total 72 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{72}{9}$ = 8

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

X $X-\bar X$ $(X-\bar X)^{2}$

7 7 - 10 = -3 9

10 10 - 10 = 0 0

12 12 - 10 = 2 4

11 11 - 10 = 1 1

8 8 - 10 = -2 4

Total 90 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{90}{9}$ = 10

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the new standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged as we see in the case of variance or standard deviation.

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3 years ago

Which pair of terms can be used to represent any two consecutive odd numbers?

ehidna [41]

Answer:

x and 2x+1

Step-by-step explanation:

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2 years ago