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den301095 [7]
4 years ago
11

***Please Help***

Mathematics
1 answer:
borishaifa [10]4 years ago
7 0
The correct answer is b
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The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran
VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0
4 years ago
Attachment answer onlyyyyyyyyyyyyyy
IRISSAK [1]

Answer:

Hey!

Your answer is Y= -2x + 9!!

Step-by-step explanation:

hope this helps!!

8 0
3 years ago
Read 2 more answers
What is the solution to this system of equations?
tia_tia [17]

Answer:

(2,4) is the solution of the equation.

Step-by-step explanation:

Basically, the solution is the two points intersecting at a point. So, (2,4) is the solution of the equation.

Hoped this helped.

8 0
3 years ago
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A car rental agency advertised renting a car for $27.95 per day and $0.24 per mile. If Kevin rents this car for 3 days, how many
lyudmila [28]

Answer:

692 miles

Step-by-step explanation:

1. 27.95 x 3 = 83.85

2. 250 - 83.85 = 166.15

3. 166.15/0.24 = 692 (answer without decimals)

6 0
3 years ago
A soldier started patrolling around his camp at 22 30 . His patrol lasted 3 hours and 20 minutes .What time did his patrol end
baherus [9]

Answer:01 50 Hrs

Step-by-step explanation:

If the soldier started patrol at 2230 hrs and his petrol lasted for 3 hours and 20 minutes, that means he was on patrol for that time.

The time he finished was therefore:

= 2230 + 320

= 2550

At 24 you begin at 0:00am so:

= 2550 - 2400

= 150

Patrol ended at 0150 hrs

4 0
3 years ago
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