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2 years ago

5

Pizza Palace charges $13.25 for a plain cheese pizza and $.75 for each additional topping. If a cheese pizza with toppings costs

$18.50, how many toppings are on it?

1 answer:

just olya [345]2 years ago

8 0

Answer:

7

Step-by-step explanation:

$18.50-$13.25=$5.25

$5.25/$0.75=7

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Jade buys a blouse and a skirt for 3/4 of their original price. Jade pays a total of $31.50 for the two items. If the original p

Norma-Jean [14]

3/4 times 18= 13.5
31.5-13.5=18
It cost 18 dollars for the skirt with a discount.
It cost 13.5 for the blouse as opposed to the original price of 18 dollars.
18(skirt)+13.5(blouse)=31.5
If you set up a proportion to find the original price of the skirt you will get the answer.
18/x=75/100
75x=18 times 100
75x=1800
75x/75=1800/75
x=24
The original price of the skirt is 24 dollars.

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2 years ago

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yuradex [85]

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2 years ago

-3 (2m+5)+8=5 (-2m+1)

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3 years ago

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PLEASE HELP ASAP!! (Find the surface area of the prism) SHOW WORK! (Number 6)

Leokris [45]

Sa= bw+hw+lw+ $\frac{1}{2}bh$ (2)
SA=(12*4)+(16*4)+(20*4)+( $\frac{1}{2} 12*16*2$ )
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2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

so

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago