$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\
5=\sqrt{(-1-2)^2+(-2-y_1)^2}\\
\sqrt{9+4+4y_1+y_1^2}=5\\
y_1^2+4y_1+13=25\\
y_1^2+4y_1-12=0\\
y_1^2+6y_1-2y_1-12=0\\
y_1(y_1+6)-2(y_1+6)=0\\
(y_1-2)(y_1+6)=0\\
y_1=2 \vee y_1=-6\\\\
\boxed{(2,2),(-6,2)}

$

3 0

3 years ago

How do you simply 3x-7+9-2x=x+2

Gre4nikov [31]

Answer:

x+2=x+2

Step-by-step explanation:

Combine like terms

3x+(-2x) and (-7)+9

x+2=x+2

7 0

2 years ago

Solve x2 + 14x = −24 by completing the square.<br><br> What is the solution set of the equation?

yan [13]

Hope this helps with the question :)

3 0

2 years ago

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