1.33333333333333333333333333333333333333333333333
or 1.33
You order the y-values from greatest to least, which are 2, 2, 3, and 4. You don't need to duplicate the same y-values, so the range is {2, 3, 4}
Answer:
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- <u><em>Event A: 1/35</em></u>
- <u><em>Event B: 1/840</em></u>
<u><em></em></u>
Explanation:
<u>Event A</u>
For the event A, the order of the first 4 acts does not matter.
The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.
Thus, the number of ways that the first <em>four acts</em> can be scheduled is:


And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).
Therefore the<em> probability of Event A</em> is:

Event B
Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.
The number of ways in which <em>four acts </em>can be scheculed when the order matters is:


The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)
Therefore, <em>the probability of Event B</em> is:

First, use distributive property on the right half.
2 * 5 = 10
2 * 2n = 4n
4n - 9 = 10 + 4n
Add 9 to both sides
4n = 19 + 4n
Subtract 4n from both sides
0 = 19
But thats not true. Therefore, there is no solution.