3 years ago

Find the complex conjugate of z1 of z1=8+i

Mathematics

1 answer:

kakasveta [241]3 years ago

8 0

Answer:

this is just math jargon... a conjugate is the same numbers but with an opposite sign.. got it?

Step-by-step explanation:

z1' ( the prime is often used for conjuates it's also used in calculus but later)

Z1' =8-i

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natta225 [31]

Answer:

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Second Box: It has all perfect squares

Third Box: see my work

Step-by-step explanation:

We have the equation $4x^2=36$

Before we do anything, let us bring all of the terms to the left side

$4x^2-36=0$

Now that we have moved the terms to one side, it is clear that we have a difference of squares.

-Work-

$4x^2=36\\\\4x^2-36=0\\\\(2x+6)(2x-6)=0\\\\$

$2x+6=0\\\\2x=-6\\\\x=-3$

$2x-6=0\\\\2x=6\\\\x=3$

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Given:

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Solution:

We have,

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Now,

$C(d(10))=0.09(800)$ $[\because C(d)=0.09d]$

$C(d(10))=72$

Therefore, the value of $C(d(10))$ is 72.

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Answer:

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Step-by-step explanation:

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Answer:

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