Question

If xsquared+ysquared=57 , xy=3 . find the value of 3(x+y)squared

Answer 1

Answer:

189

Step-by-step explanation:

If you mean this, my answer is 3x63= 189

${x}^{2} + {y}^{2} = 57 \\ xy = 3$

${x}^{2} + {y}^{2} + 2xy = 57 + 2 \times 3$

${(x + y)}^{2} = 63$

$3 {(x + y)}^{2} = 3 \times 63 = 189$