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alukav5142 [94]
3 years ago
9

If xsquared+ysquared=57 , xy=3 . find the value of 3(x+y)squared

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

189

Step-by-step explanation:

If you mean this, my answer is 3x63= 189

{x}^{2}  +  {y}^{2}  = 57 \\ xy = 3

{x}^{2}  +  {y}^{2}  + 2xy = 57 + 2 \times 3

{(x + y)}^{2}  = 63

3 {(x + y)}^{2}  = 3 \times 63 = 189

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sergiy2304 [10]
In an arithmetic sequence, the next term is found by adding a constant term to each number to arrive at the next number. The common difference can be found by subtracting the first term from the second term.

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-8.6 + 3.6 = -5.0
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1.4 + 3.6 = 2.2
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3 years ago
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