Answer:
A. It has reflectional symmetry
B. It is symmetrical
D. It has five lines of symmetry
Step-by-step explanation:
we know that
A regular pentagon has 5 sides and 5 lines of symmetry. The number of lines of symmetry in a regular polygon is equal to the number of sides
Every regular polygon has reflectional symmetry
Regular polygons are symmetrical
therefore
A. It has reflectional symmetry ------> Is true
B. It is symmetrical -----> Is true
C. It has exactly one line of symmetry ----> Is false
D. It has five lines of symmetry -----> Is true
First Of All Please Follow This
PEMDAS
P: ()
E:^
M:x
D:/
A:+
S:-
6 x (15 - 7) - 4
6 x (8) - 4
48 - 4
44
Answer: C
solve for y by subtracting 3x from each side
-4y = -3x+8
divide by -4
y = 3/4 x -2
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
