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3 years ago

Just runs 11 miles in 67 minutes how many miles does he run per minute

Mathematics

1 answer:

alina1380 [7]3 years ago

8 0

Answer

Just runs 7 minutes per mile

Step by Step explanation

Divide 11 by both numbers which leaves you with

1/6

Because you have to divide 11 by 11 and 67 by 11

when you calculate it you get 6.090909091

so you can round it to 7.

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What is the average rate of change over the interval [0, 4]?

choli [55]

Answer:

$\frac{3}{4}$

Step-by-step explanation:

Given:

Interval, [0, 4]

Required:

Average range of change over [0, 4]

SOLUTION:

Find f(0) and f(4) from the graph:

$f(0) = 0$ (when x = 0, y = 0)

$f(4) = 3$ (when x = 4, y = 3)

Average rate of change = $\frac{f(b) - f(a)}{b - a}$

Where,

$a = 0, f(a) = 0$

$b = 4, f(b) = 3$

Plug in the values into the formula for average rate of change.

$= \frac{3 - 0}{4 - 0}$

$= \frac{3}{4}$

Average rate of change $= \frac{3}{4}$

8 0

3 years ago

Please help will give brainliest! :)

Romashka-Z-Leto [24]

The answer is 13 square units :)

4 0

2 years ago

Read 2 more answers

Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0

3 years ago

What are the zeros of the function?<br> f(x) = 2x^3 – x^2 – 6x

Mars2501 [29]

i think - 3/2?.. idk

8 0

3 years ago

3) 8p + 7q = 43<br>2 -7=-q<br>how can I solve this with substitution?

Bess [88]

Answer:

p=1, q=5. (1, 5).

Step-by-step explanation:

8p+7q=43

2-7=-q

------------------

-q=-5

q=5

--------

8p+7(5)=43

8p+35=43

8p=43-35

8p=8

p=8/8=1

6 0

2 years ago

Just runs 11 miles in 67 minutes how many miles does he run per minute​

Just runs 11 miles in 67 minutes how many miles does he run per minute