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3 years ago

Just runs 11 miles in 67 minutes how many miles does he run per minute

Mathematics

1 answer:

alina1380 [7]3 years ago

8 0

Answer

Just runs 7 minutes per mile

Step by Step explanation

Divide 11 by both numbers which leaves you with

1/6

Because you have to divide 11 by 11 and 67 by 11

when you calculate it you get 6.090909091

so you can round it to 7.

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Using ABC, identify the ratio for sine of C

Stolb23 [73]

Answer:

BA / AC

Step-by-step explanation:

Given the triangle ABC;

To obtain the Sin C

Defining the attached triangle with respect to C:

Sine = opposite / hypotenus

Sin C = BA / AC

Hence, the ratio of sinC is BA /AC

4 0

2 years ago

The perimeter of a triangle with two equal sides is 50 cm. If its base were lengthened by 3 cm and each leg were shortened by 4

Nataly [62]

Answer:

Base of the original triangle is 12 cm.

Step-by-step explanation:

Let base of triangle be x

two equal legs of triangles by y

therefore perimeter of triangle

x+y+y = 50 or x+2y =50

according to the question

if base is x+3 and leg is y-4

then both are equal

that is x+3 = y-4

y-x = 7 or y =x+7

x+2y =50

x+2(x+7) = 50

x+2x +14 =50

3x +14 =50

3x = 50 -14

3x = 36

x = 12

therefore base of the original triangle is 12 cm

6 0

3 years ago

The manager at the local auto shop has found that the probability that a car brought into the shop requires an oil change is 0.8

Ber [7]

Answer:

0.85

Step-by-step explanation:

Given two events A and B, the probability that either A or B occurs is given by:

$p(A\cup B) = p(A)+p(B)-p(A\cap B)$

where

$p(A)$ the probability that A occurs

$p(B)$ is the probability that B occurs

$p(A\cap B)$ is the probability that both A and B occur at the same time

In this problem, we know the following facts:

$p(o) = 0.83$ is the probability that the car requires an oil change

$p(b)=0.17$ is the probability that the car requires a brake repair

$p(o\cap b) = 0.15$ is the probability that the car requires both an oil change and brake repair

Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:

$p(o\cup b)=p(o)+p(b)-p(o\cap b)=0.83+0.17-0.15 = 0.85$

4 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

Maksim231197 [3]

Answer:

A= 50oz milk + 2 oz cheese

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Just runs 11 miles in 67 minutes how many miles does he run per minute​

Just runs 11 miles in 67 minutes how many miles does he run per minute