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4 years ago

PLEASE HELP ME!!!

Mathematics

1 answer:

Rashid [163]4 years ago

7 0

Step-by-step explanation:

We need to find the value of angle D so that we can solve for X. To do that we need to find the value of angle A and that value will be the same value as D because these angles are the same.

To do that we have to add angles C and B together and that equals 118°. Then we have to realize that all the angles of a triangle add up to 180°. So then we have to subtract 118° from 180° and that equals 62°. So now we have the value of A.

If the value of angle A is 62° then that must be the value of angle D because these two angles are the same. So now that we have the value of angle D we need to solve for X. This equation is asking what times 2 equals the value of X. We know the value of X is 62°. So what times 2 equals 62°?

31×2=62°

Therefore the value of X is 31

Hope this helps! If you have any more questions or you need further clarification please comment down below or message me! Good luck!

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Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam

notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3 $\sigma_p$

and U.C.L = p + 3 $\sigma_p$

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

On substituting p = 0.054 and n = 100, we get

$\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }$

= 0.0226

c) The control limits for the control chart are:

Upper control limit = p + 3 $\sigma_p$

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3 $\sigma_p$

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

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1 year ago

Abdul is on his way home in his car. He has driven 18 miles so far, which is two-thirds of the way home. What is the total lengt

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4 years ago