100 is the I hope I helped
Answer:
wheres the graph if u show me the graph ill be glad to help u
Step-by-step explanation:
3 and 7 have a gcf of 1
5 and 11 have a gcf of 1
17 and 23 have a gcf of 1
Please find illustration attached
Answer and explanation:
I have illustrated the bisection of the lines using a diagram so it's easier to solve length of AB
Comparing line DE and CB, we know that DE is half of line DC and DC is half of CB, because CB= AC
Therefore DE is a quarter of line CB because length of DE × 4 will be equal to CB
To find length of AB, we go from known to unknown
We know from what we are given that line AB has a midpoint C, CB in line AB = 3x²+3x
CB=AC because CB is half of line AB
Therefore line AB
=3x²+3x+3x²+3x
= 6x²+6x
Answer:
Norma performed best on the aptitude test and should be offered the job.
Step-by-step explanation:
We are given that three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below. Tobias got a score of 74.7; this version has a mean of 61.7 and a standard deviation of 13. Norma got a score of 351; this version has a mean of 291 and a standard deviation of 25. Vincent got a score of 7.38; this version has a mean of 6.9 and a standard deviation of 0.4.
Now, to find which of the applicants should be offered the job, we have to find the z-score of each of the applicants, and the one who gets the highest z-score will get the job.
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = mean and = standard deviation
Firstly, we will find the z-score for Tobias;
The z-score of 74.7 =
= = 1
Now, we will find the z-score for Norma;
The z-score of 351 =
= = 2.4
Now, we will find the z-score for Vincent;
The z-score of 7.38 =
= = 1.2
As we can clearly see that the z-score is highest for Norma which means that Norma performed best on the aptitude test and should be offered the job.