x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
The domain is two and the range is -4
Answer:
the answer is x=6
Step-by-step explanation:
hoped I helped
Answer:
the domain is 5 and the range is 10
Step-by-step explanation:
It’s B. k. If you think about it and try to solve it in a notebook you’ll get the answer. Hope this helps
