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koban [17]
2 years ago
11

What is the greatest common factor of the terms 14c-2dand 42c3d ?

Mathematics
1 answer:
AlekseyPX2 years ago
7 0
That would be 14c^2d
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Miranda opened a checking account with $560 from her summer job. She
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Answer:

69 :D

Step-by-step explanation:

its a funny number :v

6 0
3 years ago
Using trial and improvement, find the solution between 5 and 6 for the following equation:
STALIN [3.7K]

Answer:

2

Step-by-step explanation:

that is √ 14 which is 27 ×>44.2177

4 0
2 years ago
Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
Fittoniya [83]
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive

We are given
P(A)=0.75  [ probability that Nathan is allergic ]
P(T|A)=0.98  [probability of testing positive given Nathan is allergic to Penicillin]

We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)

From definition of conditional probability,
P(T|A)=P(T n A)/P(A) 
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A) 
P(T n A) = 0.75*0.98 = 0.735




3 0
3 years ago
Chris is buying a new I-phone at the discount of 10%. The original price is $399.99. How much money will he pay for his new phon
kodGreya [7K]

Answer:

chris needs to pay 10% off that amount (aka the orignal amount)

Step-by-step explanation:

5 0
2 years ago
Mr. smith has 5 courses he teaches at the community college. his course a has 102 students with an average tardiness of 3 studen
Furkat [3]

The percentage of tardiness among the 102 pupils is 2.94.

<h2>Calculation of the percentage</h2>

According to the query,

Course A: Total number of students = 102

                   Number of tardy students = 3

Percent of students tardy in course A = (number of tardy students/total  

                                                                   number of students) * 100

  =(3/102)*100

  = 2.941

  ≈2.94

In case of course B: Total number of students = 85 & tardy student = 5

So, the percent of tardy student = (5/85)*100 = 5.88 %

Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.

Learn more about the percentage here:

brainly.com/question/92258

#SPJ4

5 0
2 years ago
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