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Roman55 [17]
3 years ago
6

What is halfway between 1/3 and 1/2

Mathematics
2 answers:
docker41 [41]3 years ago
4 0
First, divide 1 by 3 and 1 by 2.

1 divided by 3 = <span>0.33333333333

1 divided by 2 = 0.5

Add them up. </span>0.33333333333 + 0.5 = <span>0.83333333333.

Divide </span>0.83333333333 by 2, since there are 2 numbers we added up. 0.83333333333 / 2 = 0.41666666666, and <span>0.41666666666 as a fraction is 5/12.</span>
bekas [8.4K]3 years ago
3 0
1/3 = 2/6
1/2 = 3/6

Since there is no integer between 2 and 3, we must do some more working out;

1/3 = 2/6 = 4/12
1/2 = 3/6 = 6/12

The numerators (4 and 6) are both whole numbers and we know that 5 is between them, meaning that;

5/12 is bigger than 4/12 but smaller than 6/12

5/12 is between 1/3 and 1/2
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Then : False (answer B)
6 0
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The gas tank of a 2013 Honda Accord holds 17.2 gallons. How many pounds of carbon dioxide are produced by burning an entire tank
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8 0
2 years ago
If there are 120 calories in 4 ounces of hot fudge, how many calories are in 8
miss Akunina [59]

Answer:

240 calories

Step-by-step explanation

You're doubling the amount of fudge, so double the amount of calories. You could also think of it as 2 4-oz portions of fudge, then just add the calories (120+120) together.

3 0
3 years ago
Please help explanation if possible
Eva8 [605]

Answer:

612 adults

361 students

Step-by-step explanation:

To solve this question, set two equations:

Let x be number of adults and y be number of students.

As there are in total 937 people, the equation would be the sum of both adults and children:

x+y=937

x=937-y  ...... ( 1 )

As the total sale amount is $1109, the equation would be to add up the ticket fee:

2x+0.75y=1,109  ...... ( 2 )

Put ( 1 ) into ( 2 ):

2(937-y)+0.75y=1,109

1874-2y+0.75y=1,109

-1.25y=-765

y=763/1.25

y=612

Put y into ( 1 ):

x=973-612

x=361

Therefore there are 612 adults and 361 students.

5 0
2 years ago
Find the integer that makes this subtraction statement true -3 - ? = -5
Elenna [48]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}

Step-by-step explanation:

Let the missing integer be x

Solve for x

\sf{ - 3 - x =  - 5}

Move 3 to right hand side and change it's sign

\dashrightarrow{ \sf{ - x =  - 5 + 3}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\dashrightarrow{ \sf{ - x =  - 2}}

Change the signs of both sides

\dashrightarrow{ \boxed{ \sf{x = 2}}}

Hope I helped!

Best regards! :D

7 0
3 years ago
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