Answer:
4 (-1-11) + 2 (17)
Answer 2 is -14
Step-by-step explanation:
Answer:


As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Emilia case
Let X the random variable that represent the scores of a test, and we know that
Where
and
The z score formula is given by:
Since Emilia made 83 points we can find the z score like this:

Ferdinand case
Let X the random variable that represent the scores of a test, and we know that
Where
and
The z score formula is given by:
Since Ferdinand made 79 points we can find the z score like this:

As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.
Answer:
A. Q = 15 °C
B. 0.4 °C
C. Q = 23 °C
Step-by-step explanation:
The following equation models the temperature of Quin's home,
Q = 15 + 0.4t
Where Q is the temperature in degree Celsius and t is the time in minutes
A. What was the temperature when Quinn returned from vacation?
At this time, t = 0 since Quin is just arrived
Q = 15 + 0.4(0)
Q = 15 °C
B. how much does the temperature increase every minute?
0.4(t)
0.4(1)
0.4 °C
The temperature increases by 0.4 centigrade every minute.
C. How much will the temperature increase if Quinn leaves the heat on for 20 minutes
For t = 20 mins
Q = 15 + 0.4(20)
Q = 15 + 8
Q = 23 °C
So you're adding up .1, .002, and .000 003.
0.1 + 0.002 + 0.000003 = 0.102 003, or B.

is undefined if the argument

is negative, so you first need to require that

We're not done yet, though, because

still doesn't exist when

, so we remove this from the domain and we're left with

, or in interval notation,

To find the range, consider the limits of the function as you approach either endpoint of the domain.


Since

is positive everywhere, the range is