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nevsk [136]
3 years ago
8

When quin returned from vacation,he turned the heat back on his home.he set the temperature as high as it could go. Q represents

the temperature in Quinn’s home (in degrees Celsius) after t minutes.
Q = 15 + 0.4t


A. What was the temperature when Quinn returned from vacation?


B.how much does the temperature increase every minute?


C. How much will the temperature increase if Quinn leaves the heat on for 20 minutes
Mathematics
1 answer:
lozanna [386]3 years ago
3 0

Answer:

A. Q = 15 °C

B.  0.4 °C

C. Q = 23 °C

Step-by-step explanation:

The following equation models the temperature of Quin's home,

Q = 15 + 0.4t

Where Q is the temperature in degree Celsius and t is the time in minutes

A. What was the temperature when Quinn returned from vacation?

At this time, t = 0 since Quin is just arrived

Q = 15 + 0.4(0)

Q = 15 °C

B. how much does the temperature increase every minute?

0.4(t)

0.4(1)

0.4 °C

The temperature increases by 0.4 centigrade every minute.

C. How much will the temperature increase if Quinn leaves the heat on for 20 minutes

For t = 20 mins

Q = 15 + 0.4(20)

Q = 15 + 8

Q = 23 °C

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Find the future value of the loan. $34300 loan at 3.5% for 4 months
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Answer:

The future value of loan amount after 4 months is $ 34,695.136  

Step-by-step explanation:

Given as :

The loan principal = $ 34300

The rate of interest applied = 3.5 %

The time period = 4 months = \frac{1}{3} year

Let The amount after 4 months = $ A

<u>From compounded method</u>

Amount = Principal × (1+\dfrac{\textrm Rate}{100})^{Time}

or, Amount = 34300 × (1+\dfrac{\textrm 3.5}{100})^{\frac{1}{3}}

or, Amount = 34300 × (1.035)^{\frac{1}{3}}

or, Amount = 34300 × 1.01152

∴ Amount = $ 34,695.136

Hence The future value of loan amount after 4 months is $ 34,695.136  Answer

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4 0
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Six houses are located along the same road; the distances are shown. Where should the school bus stop to make the sum of distanc
sukhopar [10]
Hey there :)

Now lets name each house

    A             B              C              D             E                  F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft   <->   2000ft

Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) +  500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft

at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft

at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft

Do the same for D ,  E  and F

at D
= 6000 ft

at E 
= 7000 ft

at F
= 15000 ft

You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible. 
8 0
3 years ago
Read 2 more answers
Simplify completely the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.
Elanso [62]

Answer:

(A) 3x^3+5x+2

Step-by-step explanation:

To Simplify:  The quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.

Solution: The given statement can be easily rewritten as:

The quantity 3 times x to the 4th power=3x^4,

5 times x to the 2nd power=5x^2 and

2 times x =2x

Thus, according to the statement, the expression can be written as:

\frac{3x^4+5x^2+2x}{x}

⇒3x^3+5x+2

which is the required simplified expression.

Thus,option A is correct.

5 0
3 years ago
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