I just don't know where to start. I'm doing Algebra 2 stuff with sohcahtoa.

Mathematics

2 answers:

Tema [17]3 years ago

8 0

Hello,

For the 18 , see picture jointed.

mezya [45]3 years ago

7 0

Hello!

As you can see, 22 is the opposite angle. We are looking for the adjacent angle. Let's just call it x. Using SOH CAH TOA, we see that the tangent is the opposite divided by the adjacent side. Let's use that.

tan54≈1.38

This gives us the equation below.

1.38=22/x

Let's solve this equation for x.

1.38x=22

x=22/1.38

x=15.94

Therefore, the length of the shadow is about 15.94 meters.

I hope this helps!

You might be interested in

A terminal ray passes through (12,-5). Fine the value to all six trig functions

Harman [31]

Okay, here we have this:

Considering the provided angle, we are going to calculate the requested trigonometric functions, so we obtain the following:

So the first thing we will do is calculate the length of the hypotenuse, that is, the distance between the given point and the origin, then we have:

$\begin{gathered} r=\sqrt{(12-0)^2+(-5-0)^2} \\ r=\sqrt{12^2+(-5)^2} \\ r=\sqrt{144+25} \\ r=\sqrt{169} \\ r=13 \end{gathered}$

Now we proceed to find the value of each ratio:

$sin\beta=\frac{y}{r}=\frac{-5}{13}$ $cos\beta=\frac{x}{r}=\frac{12}{13}$ $tan\beta=\frac{y}{x}=\frac{-5}{12}$ $csc\beta=\frac{r}{y}=\frac{13}{-5}=-\frac{13}{5}$ $sec\beta=\frac{r}{x}=\frac{13}{12}$ $cot\beta=\frac{x}{y}=\frac{12}{-5}=-\frac{12}{5}$

8 0

2 years ago

What is an equation of the vertical line that passes through (-2,-9)

madam [21]

check the picture below.