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2 years ago

9

Please help will mark brainlist please and thank you

1 answer:

rosijanka [135]2 years ago

4 0

Answer:

c

Step-by-step explanation:

and the answer is c

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Mingfa says, "My sister and I have $130 altogether. If my mother gives me another

quester [9]

Given:

Total amount of Mingfa and her sister = $130

If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.

To find:

How much money does Mingfa actually have?

Solution:

Let, Mingfa have $x and her sister has $y initially. Then,

$x+y=130$ ...(i)

If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.

$x+10=3y$ ...(ii)

Substitute the value of x from (ii) in (i).

$(3y-10)+y=130$

$4y=130+10$

$4y=140$

Divide both sides by 4.

$y=35$

Putting $y=35$ in (i), we get

$x+35=130$

$x=130-35$

$x=95$

Therefore, Mingfa have $95.

8 0

2 years ago

Suppose you are choosing between checking account A, which charges a $7.50 monthly fee, $1 per check, and $2 per ATM visit; and

Kisachek [45]

I'd go with Checking account B because its cheaper .

8 0

2 years ago

(-7x∧5 + 14 - 2x) + (10x∧4 + 7x + 5x∧5)

Maslowich

$-7x^5 + 5x^5 +10x^4 -2x + 7x + 14= -2x^5 +10x^4 +5x + 14$

Your answer is $-2x^5 +10x^4 +5x + 14$

7 0

3 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em> $1.85 \times 10^{10}$ <em> liters each year</em>

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

<em>Hence, the number of liters used is </em> $1.85 \times 10^{10}$ <em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0

2 years ago

Andrew has already played 32 minutes on his video game this morning and wants to play an additional 15 minutes on each of x game

belka [17]

Given :

Andrew has already played 32 minutes on his video game this morning and wants to play an additional 15 minutes on each of x games after school today.

To Find :

Which equation can be used to find y, the total minutes Andrew will play video games today.

Solution :

Number of minutes he play after school time, n = 15x .

Number of minutes already played, c = 32 .

So, total number of minutes he play games for today is :

y = n + c

y = 15x + 32

Therefore, equation which is useful to find number of minutes video game played per day is y = 15x + 32 .

8 0

2 years ago