All categories

3 years ago

describe the transformation of the function f(x)=1/2x-2 that makes the slope two and the Y intercept -8

Mathematics

2 answers:

Effectus [21]3 years ago

6 0

Answer:

Reflect over the axis of y=x-4

Step-by-step explanation:

f(x)=1/2x-2

g(x)=2x-8

axis of reflection: y=x-4

(This is my best guess)

GarryVolchara [31]3 years ago

4 0

Answer:

hi love you have a nice day

Step-by-step explanation:

You might be interested in

We need a minimum of 30 book sales by today. If 10 books were sold yesterday, what are the possible numbers for sales today

amm1812

I mean it would be A and D because I don't know why they are both the same answer. If 10 books were sold yesterday, at LEAST 20 are needed to make the goal.

6 0

2 years ago

Please help: what is 2+4+4+10? I will five brainliest

telo118 [61]

Answer:

It is 20

Step-by-step explanation:

Use your fingers if necessary

5 0

3 years ago

A highway engineer specifies that a certain section of roadway covering a horizontal distance of 2km should have a downgrade of

Zigmanuir [339]

Answer:

$0.16km$

Step-by-step explanation:

A highway engineer wants to compute the change in elevation of a section of road. The horizontal distance of this section of road is 2km and downgrade is 8%

The slope formula is given by

$m=\frac{rise}{run}=\frac{x}{y}$

m = 8% = 8/100

run = y = 2km

$m =\frac{x}{y}$

$\frac{8}{100} =\frac{x}{2}$

$\frac{2*8}{100} =x$

$x=\frac{16}{100} =0.16km$

Verification:

$m=\frac{0.16}{2}= 0.08=8%$ %

3 0

3 years ago

Read 2 more answers

Please help with the answer for 7/9 -1/3=

Levart [38]

Answer:

4/9 is the answer

Hope it correct and it helps

6 0

2 years ago

Read 2 more answers

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

d1i1m1o1n [39]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

4 0

2 years ago

Read 2 more answers