Answer:
Option C
Step-by-step explanation:
The standard form of equation of a cirle is:
(x-h)^2+ (y-k)^2=r^2
In the given question as the point is given and the radius of circle is given:
So,
(h,k)=(2,-1)
and
r=3
Here,
h=2
k= -1
Putting the values of h,k and r in standard form
(x-2)^2+ (y-(-1))^2=(3)^2
(x-2)^2+ (y+1)^2=(3)^2
So the equation of circle is:
(x-2)^2+ (y+1)^2=9(3)^2
Option C is the correct answer ..
Answer:
Step-by-step explanation:
Answer:
oh wow let me garba cac
Step-by-step explanation:
Answer:
The answer is B. His slope should be positive because the trend line is slanted up to the right.
Step-by-step explanation:
This answer is correct because the thred line is slanted up to the right, so it makes it positive. "His slope should be positive because the coordinates of all the plotted points are positive." is wrong because all the coordinates plotted positive isn't a valid reason. The other answers are wrong because the slope is positive.
Answer:
<h3>
f(x) = 6(x - 2)² + 3</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - vertex form of the equation of the parabola with vertex (h, k)
"the parabola opens upward" means: a>0
"the parabola has x = 2 as an axis of symmetry" means: h = 2
so f(x) = a(x - 2)² + k
"the parabola contains the point (1, 9)" means:
9 = a(1 - 2)² + k
9 = a(-1)² + k
9 = a + k
k = 9 - a
"the parabola contains the point (4, 27)" means:
27 = a(4 - 2)² + k
so:
27 = a(2)² + 9 - a
27 = 4a + 9 - a
3a = 18
a = 6
and k = 9 - 6 = 3
Therefore the vertex form for this parabola is:
<u> f(x) = 6(x - 2)² + 3</u>
