3 years ago

Could someone please help mee Step by step

Mathematics

1 answer:

Keith_Richards [23]3 years ago

8 0

Let Q be the point (a, b). Since the midpoint of P (2, 3) and Q (a, b) is (4, 6), we have

(2 + a)/2 = 4

(3 + b)/2 = 6

Solve for a and b :

(2 + a)/2 = 4

2 + a = 8

a = 6

(3 + b)/2 = 6

3 + b = 12

b = 9

So the coordinates of Q are (6, 9).

You might be interested in

If log(10) s=4 then what does s =

user100 [1]

Answer: c d e

Step-by-step explanation:

its so easy

6 0

3 years ago

How can you tell when the LCM of two numbers will equal one of the numbers or equal the product of the numbers

Vladimir79 [104]

When one number will divide exactly into the other one then the other one will be the LCM. For example the LCM of 4 and 8 = 8 .

When they do not divide as above then the product of the numbers may be the LCM. For example the LCM of 3 and 4 = 3*4 = 12.

The product is not always the LCM. It might be a lower number . For example the LCM of 4 and 6 is not 24 but 12. ( 24 / 2).

7 0

3 years ago

In a class of 24 students, 25 percent of them failed a test. How many students failed a test

Tcecarenko [31]

X/24 = 25/100
100x = 600
100x/100 = 600/100
x = 6
6 students failed the test

4 0

3 years ago

Read 2 more answers

Find the value of x.

pishuonlain [190]

Step-by-step explanation:

Here we can see it is a quadrilateral so

x + 108° + 65° + 53° = 360° ( being sum of angles of quadrilateral)

226° + x =360°

x = 360° - 226°

Therefore x = 134°

6 0

4 years ago

Read 2 more answers

If the polynomials p(x)=2x³ +bx² +3x-5 and q(x)= x³+x² -4x-b leave the same remainder, when divided by x-2, prove that b = -13/5

Tju [1.3M]

Step-by-step explanation:

Lets first find the remainder when p(x) is divided by x-2

p(2)=2(2)³+b(2)²+3(2)-5

p(2)=16+4b+6-5

p(2)=4b+17

Now let's find the remainder when q(x) is divided by x-2

q(2)=(2)³+(2)²-4(2)-b

q(2)=8+4-8-b

q(2)=4-b

Now let's equate both of them

4b+17=4-b

4b+b=4-17

5b=-13

b=-13/5 as required

5 0

3 years ago