Convert both percents into decimals. To do that, move the percent sign two places to the left then multiply.
50% => 0.50
150% => 1.50
1.50 * 0.50 * x ; Start
0.75 * x ; 1.50 * 0.50 is 0.75
The final answer is 0.75 * x. Which can also be expressed as 3/4x.
Answer:
The minimum number of fish each must have caught is 90 fishes
Step-by-step explanation:
The number of fishes Tisha's net can hold = 15
The number of fishes Dana's net can hold = 18
Let the total number of fishes both Tisha and Dana caught = X
15 × A = 18 × B = X
Therefore, X is the lowest common multiple (LCM) of 15 and 18 given as follows;
15 = 3 × 5
18 = 3 × 6
Therefore, the LCM of 18 and 5 = 3 × 5 × 6 = 90
Which gives, the minimum number of fish each must have caught = 90 fishes.
Differentiate the given solution:

Substitute
and
into the ODE:

and it's easy to see the left side indeed reduces to 0.
Answer:
D
Step-by-step explanation:
2y=10x
Divide both sides by 2.
y=5x
Now substitute this into the second equation.
8n-(2n-3)=12
8n-2n+3=12
6n=12-3
6n=9
n=9/6=3/2