Start by writing out the information you know mathematically (I used S for cost of senior ticket, and C for cost of child ticket. You could use X and Y, or any other combination of letters as variables)
3s + 1c=38
3s + 2c=52
Now, you'll want to eliminate one of the variables by subtracting it out. Remember - Same sign, subtract (and therefore different sign, add).
In this case, 3s exists in the first and second equation, so it's very easy to get rid of. They're both positive, so they have the same sign (+). Same sign, subtract.
3s + 1c=38
-(3s + 2c=52)
__________
0 -1c= -14
-c=-14
C=14
Now, plug c=14 into either of the original equations.
3s + C= 38
3s + 14=38
3s=24
S=8.
So, a child ticket costs $14 and a senior ticket costs $8.
Answer:
Step-by-step explanation:
Part A:
Mark did not round to the nearest hundreds, he rounded to the nearest tens.
Option A (Incorrect):
271 and 582 are normally not rounded down, unless we are using limits coming from the left and a unique equation.
Option B (Incorrect):
271 as the same problem as option A, but 582 rounding to 600 is correct. It doesn't make sense to round both numbers differently, unless stated.
Option C (Incorrect):
271 rounding to 300 is correct, but 582 is not normally rounded down to 500 unless we are using limits coming from the left and a unique equation. Unless stated, don't round both numbers differently.
Option D (Correct):
271 rounded to 300 and 582 rounded to 600 looks correct for rounding to the hundreds.
Part B:
There are two ways to solve this question:
One way:
271 + 582 = 853
Round 853 to the nearest hundred for 900
(Note: Round 853 to the nearest tens for 850.)
Second way:
271 + 582
Round Numbers:
300 + 600
= 900
Answer:
13 units
Step-by-step explanation:
(x₁,y₁) = (-5 , 3) & (x₂ , y₂) = (7 ,8)
![= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%287-%5B-5%5D%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B%287%2B5%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%20%5Csqrt%7B%2812%29%5E%7B2%7D%2B%285%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B25%7D%5C%5C%5C%5C%3D%5Csqrt%7B169%7D%5C%5C%5C%5C%3D%2013)
Answer:
As a statistical tool, a frequency distribution provides a visual representation for the distribution of observations within a particular test. Analysts often use frequency distribution to visualize or illustrate the data collected in a sample.
