Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Yes, you can see by subtracting 32 from the bottom sides and seeing that the correspondent for 20 degrees celcius is double that of the correspondent for 10 degrees celcius
B(cone)=B(pyramid)=r²π
V(pyramid)=1/3 * B * H = 1/3 * r² π * 3 r ( 3 will cancel out )= r³ π
Answer: r³ π
Answer:
x^2 ×1 2x + 36
Step-by-step explanation:
area of a square = L × B
= (x+6) (x+6) since a square has 4 equal sides, it becomes (x+6) (x+6)
= x(x+6) +6(x+6)
= x^2 + 6x + 6x +36
= x^2 + 12x +36 added all the like terms 6x + 6x = 12x
hope this helps ☆☆☆
