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Len [333]
3 years ago
8

Naomi is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.35%. If Nao

mi would like to end up with $16,000 after 23 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.
A=d(i(1+i)n−1​)
Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

brainliest please?

Step-by-step explanation:

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Triangle A is reflected in the x axis to give triangle B, which is then reflected in the line y=x to give Triangle C. Draw Trian
OLEGan [10]

Step-by-step explanation:

always draw triangle b first. for triangle b it is reflected across the x-axis which means all y valies become negative. then for triangle c, you swap the x and y values around.

5 0
2 years ago
What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?
Daniel [21]
Our angle teta is:
teta = 3pi/4

since that is larger than pi/2 but less than pi that means that our angle lies in II quadrant (x negative y positive)

sin(3pi/4) = √2/2
cosine and tangent of that angle must be negative because of position of the angle.

cos(3pi/4) = -√2/2
tan(3pi/4) = -1
7 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
A high school has 40 players on the football team. The summary of the players' weights is given in the box plot. Approximately,
yulyashka [42]

Answer:

About 91%

Step-by-step explanation:

According to the box plot provided :

Total number of students = 40

Minimum weight = 152 pounds

Third quartile (Q3) = 245

The approximate percentage of students that weigh 245 kg or less

About 10 of the intervals out of the 11 coverage interval of the box plot fall between 152 and 254 ; Hence,

(10 / 11) * 100

90.90

= about 91 % of the total students weigh 245 kg or less

4 0
2 years ago
Using a calculator and the formula above, calculate the APR. Choose the correct answer.
GarryVolchara [31]
APR=(1+r/12)^(12)-1
APR=(1+0.16÷12)^(12)−1
APR=0.172×100
APR=17.2%
7 0
3 years ago
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