The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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$9,100
I multiplied 5000 x .082 and got 410
then i multiplied 410 x 10 and got 4,100
then i added 5000 + 4100 to get $9,100.
Answer:
her balance will be $7,560 after 9 years i believe.
Step-by-step explanation:
Answer:
The answer is Option D:
<em>"The distribution of all values of the statistic resulting from all samples of size taken from the same population."</em>
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Step-by-step explanation:
First, is a distribution of all values. It has to include all the possible values of the statistic with its associated probability.
Second, is a distribution of a statistic because we are talking about sample results.
Third, it has to be taken from the same population and have to have the same sample size.
Answer:
C. It would be shifted up.
Step-by-step explanation:
We base it off the y-intercept. Since -7 is <em>less</em><em> </em><em>than</em><em> </em>1, and our new function has a positive y-intercept, it would indeed be shifted up.
I am joyous to assist you anytime.
