Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to
we have
so
Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to
so
Multiply by 2 both sides
----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
I will not be able to explain but you can surely trust those answers
A = 130
B = 50
C = 50
D = 130
E = 75
F = 105
G = 105
H = 75
I = 40
J = 140
K = 38
L = 102
M = 38
N = 50
O = 95
P = 35
Q = 130
R = 100
S = 100
T = 80
U = 80
V = 35
W = 45
X = 40
Y = 40
Z = 60
Vertical asymptotes happen at x=a if the function is undefined at x=a.
This is a rational functions, and rational functions are not defined when the denominator is zero, since you can't divide by zero.
In this case, the denominator is zero if
And thus the function has a vertical asymptote at x= -3/2