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2 years ago

One tablespoon of ground cinnamon costs $0.36. How much does one teaspoon cost?

Mathematics

1 answer:

Bas_tet [7]2 years ago

5 0

Answer:

$0.12

Step-by-step explanation:

There are 3 teaspoons in a tablespoon, so our price will be divided by 3 because of the quantity of ground cinnamon it would cost for a teaspoon and 0.36/3=0.12

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3. The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount b

KatRina [158]

The way to get the equation for the radius (r) is to get r by itself. So divide each side by 4pi
500/4pi=r^2
Now take the square root of each side to get the equation of r.
sqrt(500/4pi)=r

6 0

2 years ago

Read 2 more answers

Given the following, what is the probability of choosing an purple marble and flipping tails?

MrMuchimi

Your answer is correct!! 2/3

4 0

2 years ago

If 14x = ^13√14, what value of x makes this equation true?

Andrews [41]

The value of x is 1/13 (4th choice)

Step-by-step explanation:

${a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }$

If 14^x = ¹³√14, what value of x makes this equation true?

$\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }$

So, the value of x is 1/13 (4th choice)

Hope it helpful and useful :)

6 0

3 years ago

A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

Let $\mu$ = average miles for deluxe tires

So, Null Hypothesis, $H_0$ : $\mu \geq$ 50,000 miles {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, $H_A$ : $\mu$ < 50,000 miles {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is One-sample z test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean lifespan = 46,500 miles

$\sigma$ = population standard deviation = 8000 miles

n = sample of tires = 28

So, test statistics = $\frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }$

= -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0

2 years ago

Randy works 50 weeks a year, averaging $500 a week in wages. He is offered a salaried position at $27,500 a year. If he accepts

blagie [28]

Answer:

b. more money

Step-by-step explanation:

Randy's original position lets him make:

50*500 = $25,000

The new position will let him make:

$27,500

Therefore,

original position < new position = $25,000 < $27,500

3 0

1 year ago