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2 years ago

Given f(x)=½(8-2x), what is the value of f(-5)? help plez

Mathematics

2 answers:

guajiro [1.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

f(x)=½(8-2x)

Let x = -5

f(-5)=½(8-2* (-5))

=½(8+10)

=½(18)

Gnoma [55]2 years ago

8 0

$\\ \tt\bull\rightarrowtail f(x)=1/2(8-2x)$

$\\ \tt\bull\rightarrowtail f(-5)$

$\\ \tt\bull\rightarrowtail 1/2(8-2(-5))$

$\\ \tt\bull\rightarrowtail 1/2(8+10)$

$\\ \tt\bull\rightarrowtail 1/2(18)$

$\\ \tt\bull\rightarrowtail 9$

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Anthony's weight is nine pounds more than twice his brothers weight. Anthony's weighs 59 pounds. how much does his brother weigh

ahrayia [7]

A = Anthony's weight
B = Anthony's brother's weight

A = 2B + 9 Plug in Anthony's weight
59 = 2B + 9 Subtract 9 from both sides
50 = 2B DIvide both sides by B
25 = B Switch the sides to make it easier to read
B = 25

Anthony's brother weighs 25 pounds.

8 0

3 years ago

Read 2 more answers

Use a unit rate to find the unknown value.

Tanzania [10]

1. 40/8 = 45/9
2. 42/14 = 15/5
3. 14/2 = 56/8
4. 8/4 = 26/13

3 0

3 years ago

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assum

attashe74 [19]

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

At 95% confidence level, the value of z is equivalent to:

z = 1.96

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

6 0

2 years ago

Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the

igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0

2 years ago

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Complete the solution of the equation. find the value of y when x equals -8 8x+8y=-48

Korvikt [17]

8x + 8y = -48
-------------------------
Plug in -8 for x
(8) (-8) + 8y = -48
-------------------------------
Simplify
(8) (−8) + 8y = −48
−64 + 8y = −48
8y − 64 = −48
-----------------------------------------
Add 64 to each side
8y − 64 + 64 = −48 + 64
8y = 16
---------------------------------------------------
Finally, divide each side by 8
8y ÷ 8 = 16 ÷ 8
y = 2
----------------------------------------------------------------
y = 2 is your answer

4 0

2 years ago