The graph of y=-3x+4 is:

Mathematics

1 answer:

Mariulka [41]2 years ago

4 0

y=-3x+4

this is a line with slope -3 and y intercept of 4

the line is all the points that are the solutions to the equation

D.a line that shows the set of all solutions to the equation

You might be interested in

According to the national institute of allergy and infectious diseases about 3.7% of american adults have a food allergy. A larg

bixtya [17]

Answer:

The mean of x is close to 14.8.

The standard deviation of x is close to 3.78.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and each trial can only have two outcomes, with probabilities $\pi$ and $1 - \pi$ .

For an experiment with n repeated trials and a probability of success $\pi$ , we have that:

The mean is: $\mu_{x} = n*\pi$

The standard deviation is: $\sigma_{x} = \sqrt{n*\pi*(1-\pi)}$

In this problem

There are 400 employees, each with a probability of 3.7% of having food allergy. So $n = 400, \pi = 0.037$ . So:

$\mu_{x} = n*\pi = 400*(0.037) = 14.8$

The mean of x is close to 14.8.

$\sigma_{x} = \sqrt{n*\pi*(1-\pi)} = \sqrt{400*(0.037)*(1-0.037)} = 3.78$

The standard deviation of x is close to 3.78.

5 0

3 years ago

Slope of (1,10) (10,8)

Bond [772]

Answer:

i hope this helps

Step-by-step explanation:

download the image below it is the answer to your problem

Download pdf

6 0

2 years ago

Find the angle between u = i+sqr of 7j and v = -i+9j. Round to the nearest tenth of a degree.

Zolol [24]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors } \\\\ cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies \measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} u=i+\sqrt{7}j\implies &\\\\ v=-i+9j\implies & \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf u\cdot v\implies (1)(-1)~+~(\sqrt{7})(9)\implies -1+9\sqrt{7}\implies 9\sqrt{7}-1~\hfill dot~product \\\\[-0.35em] ~\dotfill\\\\ ||u||\implies \sqrt{1^2+(\sqrt{7})^2}\implies \sqrt{1+7}\implies \sqrt{8}~\hfill magnitudes \\\\\\ ||v||\implies \sqrt{(-1)^2+9^2}\implies \sqrt{1+81}\implies \sqrt{82} \\\\[-0.35em] ~\dotfill$

$\bf \theta =cos^{-1}\left( \cfrac{9\sqrt{7}-1}{\sqrt{8}\cdot \sqrt{82}} \right)\implies \theta =cos^{-1}\left( \cfrac{9\sqrt{7}-1}{\sqrt{656}} \right) \\\\\\ \theta \approx cos^{-1}(0.8906496638868531)\implies \theta \approx 27.05$