Answer:
1. Angle of depression
2. Angle of elevation
3. Angle of depression
4. Angle of elevation
5. Angle of depression
6. Angle of elevation
7. Angle of depression
8. Angle of elevation
9. x=95.8 ft
10. x=173.2 ft
11. x=60ft
12. x=35.0
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Step-by-step explanation:</h2><h3>Questions 1-8: </h3>
I don't know how to explain, I'm sorry.
But if the angle is above the flat line which represents something's straight line of vision, it's a angle of elevation. If it's below, it's an angle of depression.
<h3>Question 9: </h3>
Using SOH CAH TOA, I can tell that the angle is going to use CAH.
I wrote the formula Cos40°=x/125
To isolate the x, I multiplies both sides by 125.
125Cos40°=x
I inserted my new equation into desmos, and I got 95.75555539, which I proceeded to round to 95.8.
<h3>Question 10:</h3>
Using SOH CAH TOA again, I can tell that the angle is going to use TOA.
I wrote the formula Tan30°=x/300
To isolate the x, I multiplies both sides by 300.
300Tan30°=x
I inserted my new equation into desmos, and I got 173.2050808, which I proceeded to round to 173.2.
<h3>Question 11:</h3>
For this problem, I noticed that it was a isotopes right triangle, so the two legs will be congruent.
One of the legs was 60, so the other leg must also be 60.
<h3>Question 12:</h3>
Using SOH CAH TOA again, I can tell that the angle is going to use TOA.
I wrote the formula Tan25°=x/75
To isolate the x, I multiplies both sides by 75.
75Tan25°=x
I inserted my new equation into desmos, and I got 34.97307436, which I proceeded to round to 35.0.
Please note that I am also not 100% positive about my answers.
