All categories

3 years ago

Please help me no links please

Mathematics

1 answer:

Ede4ka [16]3 years ago

6 0

Answer:

1. Angle of depression

2. Angle of elevation

3. Angle of depression

4. Angle of elevation

5. Angle of depression

6. Angle of elevation

7. Angle of depression

8. Angle of elevation

9. x=95.8 ft

10. x=173.2 ft

11. x=60ft

12. x=35.0

<h2>Step-by-step explanation:</h2><h3>Questions 1-8: </h3>

I don't know how to explain, I'm sorry.

But if the angle is above the flat line which represents something's straight line of vision, it's a angle of elevation. If it's below, it's an angle of depression.

<h3>Question 9: </h3>

Using SOH CAH TOA, I can tell that the angle is going to use CAH.

I wrote the formula Cos40°=x/125

To isolate the x, I multiplies both sides by 125.

125Cos40°=x

I inserted my new equation into desmos, and I got 95.75555539, which I proceeded to round to 95.8.

<h3>Question 10:</h3>

Using SOH CAH TOA again, I can tell that the angle is going to use TOA.

I wrote the formula Tan30°=x/300

To isolate the x, I multiplies both sides by 300.

300Tan30°=x

I inserted my new equation into desmos, and I got 173.2050808, which I proceeded to round to 173.2.

<h3>Question 11:</h3>

For this problem, I noticed that it was a isotopes right triangle, so the two legs will be congruent.

One of the legs was 60, so the other leg must also be 60.

<h3>Question 12:</h3>

Using SOH CAH TOA again, I can tell that the angle is going to use TOA.

I wrote the formula Tan25°=x/75

To isolate the x, I multiplies both sides by 75.

75Tan25°=x

I inserted my new equation into desmos, and I got 34.97307436, which I proceeded to round to 35.0.

Please note that I am also not 100% positive about my answers.

You might be interested in

Multiple please help me out. (picture is for question 4)

Cloud [144]

Answer:

1. 9/10

2. 1/5

3. 4/9

4. 1

Step-by-step explanation:

The general equation of the line is:

(y - y0) = m ( x - x0), where "m" represents the slope is: (y1 - y0) / (x1 - x0).

1. From the statement we know that (x1, y1) = (18, 17) and (x0, y0) = (8,8)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (17 - 8)/(18 - 8) = 9/10.

The slope is 9/10.

2. From the statement we know that (x1, y1) = (8, 9) and (x0, y0) = (3,8)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (9 - 8)/(8 - 3) = 1/5.

The slope is 1/5.

3. From the statement we know that (x1, y1) = (15, 15) and (x0, y0) = (6,11)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (15 - 11)/(15 - 6) = 4/9.

The slope is 4/9.

4. From the graph, we know that the line passes through the points (-5, -4) and (-7, -6). So we know that (x1, y1) = (-5, -4) and (x0, y0) = (-7,-6).

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (-4 - (-6))/(-5 - (-7)) = 2/2 = 1.

The slope is 1.

4 0

3 years ago

Pleas help me for 20 points

Montano1993 [528]

Answer:

240

Step-by-step explanation:

1 foot = 12 inches

4/3 feet = 16 inches

area = length × width

= 15 × 16

= 240 square inches

8 0

2 years ago

How many flyers can we buy?

Rudiy27

Answer: 1760

Step-by-step explanation:

Cost of 1 flyer = $0.25 or 25 cents

Budget is = $555

Let us assume that supplies cost is a one time cost

Cost of supplies for one time = $115

So budget remains =

So in $0.25 we get = 1 flyer

In $440 we get = = 1760

Hence, we can buy 1760 flyers.

hope this helped

8 0

2 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

$A=\pi[r2^{2}-r1^{2}]$