- Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.
If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2
<h2>6.</h2>
Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation: 
Next, divide both sides by -5 and your slope-intercept form is 
Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>
<h2>7.</h2>
It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:
Now since 2 <em>is</em> the negative reciprocal of -1/2, <u>these lines are perpendicular.</u>
You have to use PEMDAS (Parentheses Exponents Multiplication/Division Addition/Subtraction) to solve this,
Because you don't have any parenthesis or exponents you start with Multiplication/Division. This means you do 4*3 to get 26+5-12
Then, you move to Addition/Subtraction in which you complete left to right, So you do 26+5 to get 31-12
Finally you subtract 31-12 to get 19
Let them be X and Y..
now...
yx=100 ....
y=100/y ...
now...
x+y= s....where s is their sum...
but y=100/x
now....x+100/x=s..
by differentiating both sides with respect to x..
1-100/x^2=ds/dx
but ds/dx=0..
100=x^2 ..
x=10..
so y=10
I believe it is <span>2.5 x 10^-3 cm</span>
Answer:
"jitesh" travels 24 m towards south and then takes a turn at east and moves 5m towards it find his distance and displacement
tati
Step-by-step explanation:
"jitesh" travels 24 m towards south and then takes a turn at east and moves 5m towards it find his distance and displacement
