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Answer: 12/25</h3>
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Reason:
60% = 60/100 = 0.6 is the probability of making any given free-throw.
1 - 0.6 = 0.4 is the probability of missing any given free-throw.
We have these probabilities
- A = P(making 1st, missing 2nd) = 0.6*0.4 = 0.24
- B = P(missing 1st, making 2nd) = 0.4*0.6 = 0.24
The probability of making exactly one free throw is A+B = 0.24+0.24 = 0.48
Convert this to a fraction:
0.48 = 48/100 = (4*12)/(4*25) = 12/25
Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
727.29 + 248.50 − x ≥ 500;
x ≥ $475.79
727.29 + 248.50 − x ≤ 500;
x ≤ $475.79
727.29 − 248.50 + x ≥ 500
x ≥ $21.21
727.29 – 248.50 - x ≤ 500
x ≤ $21.21
10 would be the answer I believe.
