Answer:D( Ribosomes
Explanation: Since most enzymes are proteins, it will be produced at the ribosomes. It may have an active and an inactive form. Which means another substance Will turn it on or off.
Ribosome are where RNA is translated into protein. This process is called protein synthesis. Protein synthesis is very important to cells, therefore large numbers of ribosomes are found in cells. Ribosomes float freely in the cytoplasm, and are also bound to the endoplasmic reticulum (ER).
Answer:
Answer is C.
Explanation:
For A and B, a base substitution affects one of the three bases that comprise a codon, the DNA/RNA unit that corresponds to a particular amino acid. If one base is substituted, one codon and therefore one amino acid will be affected. Codons have built-in redundancy, so even by changing one base, the new codon sometimes still corresponds to the same amino acid. Therefore, a base substitution at most affects one amino acid, and sometimes doesn't affect it all.
Frameshift mutations cause a lot more trouble. These occur when you have a deletion or insertion that changes the number of bases in your gene. As a result, the "frame" of the codons changes (everything shifts one way or the other by the number of bases added/removed). This affects EVERY codon downstream of the mutation, so you can imagine that such a mutation would have a bigger effect the closer to the start of the gene it occurs. This is why C is correct.
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
In addition to chloride, there are other negatively charged molecules in plasma. The extra sodium restores the balance of the overall negative charges.
So this is how plasma is electrically neutral.
<h3>The makeup of bodily fluids:</h3>
- High levels of sodium, chloride, bicarbonate, and protein can be found in the plasma.
- High levels of salt, chloride, and bicarbonate but a relatively low level of protein can be found in the IF.
- The ICF, on the other hand, contains higher levels of protein, phosphate, magnesium, and potassium.
<h3>What occurs when the
plasma Na+ content rises?</h3>
- Although the plasma sodium concentration does not provide any information regarding the volume of extracellular fluid, it does allow for an assumption regarding intracellular volume.
- A rise in plasma sodium (plasma osmolality) causes water to be drawn out of the cell, which causes the intracellular volume to decrease.
<h3>Why does
plasma have a
higher sodium content than
chloride?</h3>
- In plasma, sodium predominates over chloride.
- In addition to chloride, there are other negatively charged molecules in plasma.
- The extra sodium restores the balance of the overall negative charges.
To learn more about plasma charge visit:
brainly.com/question/22196626
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