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3 years ago

Helppppppp plz thx........

Biology

2 answers:

bearhunter [10]3 years ago

6 0

Heisuuehebeiebebjejrjroeoekse

8090 [49]3 years ago

5 0

Answer:

1) aa- affected

2) Aa- unaffected carrier

3) aa- affected

4) aa- affected

5) Aa - unaffected carrier

6) Aa- unaffected carrier

7) aa- affected

8) aa- affected

9) Aa- unaffected carrier

10) aa- affected

11) Aa- unaffected carrier.

This trait is recessive.

The F1 generation has a 50/50 chance of having unaffected offspring.

Explanation:

1) Given

2) Some of the offspring have the trait, and they're not affected, so they have to be a carrier

3) The box is shaded in so they have to have the trait, which means they have to have the same gene pattern as the other affected person (#1)

4) They are also shaded in, so they have to have the trait

5) Since the parents either have the trait or are carriers, if they're not affected they have to be a carrier

6) Same reasoning as #5

7) This is shaded in, the box has to have the trait

8) Shaded in = has the trait/affected

9) Since the parents either have the trait or are carriers, if they're not affected they have to be a carrier

10) Shaded in = has the trait/affected

11) Since the parents either have the trait or are carriers, if they're not affected they have to be a carrier

Since the trait is displayed when the people have two lowercase letters (aa), and people can be unaffected and carriers, (Aa), this trait has to be recessive.

If you make a Punnett Square, you will see that half of the offspring can result in an Aa, while the other half can result in an aa, meaning there's a 50/50 chance of the offspring of the F1 (first) generation will have the trait.

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Coat color in rabbits is under the control of a single gene with

Mashcka [7]

Answer: a) Cch x Ccch

b) Ccch x Cc

c) Cch x cchch

d) cchc x chc

Explanation:

Data:

Coat color in rabbits is under the control of a single gene with

four alleles: C (full gray color); cch (chinchilla, light gray); ch

(Himalayan, white with black extremities); and c (albino, absence

of pigmentation).

The dominance hierarchy is represented as: C >cch > ch > c.

Possible genotypes:

For full gray color: CC (Gray), Ccch (Gray-2), Cch (Gray-1), Cc (Gray-3). The allele "C" dominates over the other three alleles, so in every combination where "C" is present, the animal will be fully grayed.

For light gray color/Chinchilla: cchcch (Chinchilla), cchch (Chinchilla-1), cchc (Chinchilla-2). The allele "cch" dominates over "ch" and "c", but not over "C". So if the allele "C" is combined with "cch", the animal will be fully grayed, but in any other combination with "cch", the animal will be light grayed.

For white with black extremities/Himalayan: chch (Hymalayan), chc (Hymalayan-1). The allele "ch" that determines the Himalayan color is only dominant over the allele "c". But in combination with any other allele, "ch" behaves as a recessive one.

For albino: cc. In the presence of any of the other alleles, the allele "c" always behaves as a recessive one. The only possibility of getting an albino animal is if "c" combines with another "c".

Crosses:

a) Gray-1 x gray-2

3/4 gray : 1/4 chinchilla

Parental) C ch x C cch

Gamates) C ch C cch

Punnet Square) C cch

C CC Ccch

ch Cch cchch

F1 Genotype) 1/4 CC

1/4 Cch

1/4 Ccch

1/4 cchch

F1 Phenotype) 3/4 Fully Gray animals (CC, Cch, Ccch)

1/4 Chinchilla animals (cchch)

b) Gray-2 x gray-3

3/4 gray : 1/4 chinchilla

Parental) C cch x C c

Gamates) C cch C c

Punnet Square) C cch

C CC Ccch

c Cc cchc

F1 Genotype) 1/4 CC

1/4 Cc

1/4 Ccch

1/4 cchc

F1 Phenotype) 3/4 Fully Gray animals (CC, Cc, Ccch)

1/4 Chinchilla animals (cchc)

c) Gray-1 x chinchilla-1

1/2 gray : 1/4 chinchilla : 1/4 himalayan

Parental) C ch x cchch

Gamates) C ch cch ch

Punnet Square) C ch

cch Ccch cchch

ch Cch cchch

F1 Genotype) 1/4 Ccch

1/4 Cch

1/4 cchch

1/4 chch

F1 Phenotype) 2/4=1/2 Fully Gray animals (Ccch, Cch)

1/4 Chinchilla animals (cchch)

1/4 Himalayan animals (chch)

d) Chinchilla-2 x himalayan

1/2 chinchilla : 1/4 himalayan : 1/4 albino

Parental) cchc x chc

Gamates) cch c ch c

Punnet Square) cch c

ch cchch chc

c cchc cc

F1 Genotype) 1/4 cchch

1/4 cchc

1/4 chc

1/4 cc

F1 Phenotype) 2/4=1/2 Chinchilla animals (cchch, cchc)

1/4 Himalayan animals (chc)

1/4 Albino animals (cc)

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What is a substance that increases the hydrogen ion concentration in a solution.

MissTica

Answer:

Explanation:

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The Tasmanian devil has 14 chromosomes in each of its somatic cells, 2n = 14. How many chromosomes would be present in a cell af

nikitadnepr [17]

How many chromosomes would be present in a cell after anaphase of Mitosis?
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The lungs remain inflated because ___________.a. intrapleural pressure is exactly equal to atmospheric pressure b. intrapleural

kkurt [141]

Answer:

Option C, Intrapleural pressure is less than intrapulmonary pressure

Explanation:

During inspiration, the air enters the lungs due to lower pressure in the intrapulmonary or intra-alveolar than the atmospheric pressure. During quite respiration, the intrapulmonary pressure reduces to a pressure that is 3 mm Hg lower than that of atmospheric pressure. During quiet expiration, the intrapulmonary pressure rises up to a pressure that is 3 mm Hg higher than that of atmospheric pressure. This leads to lack of air in the intrapleural space thereby producing intrapleural pressure which is lesser than that of intrapulmonary pressure.

This difference in pressure (i.e higher pressure with in the lungs than the atmosphere) causes lungs to remain attached to the chest wall and hence looks inflated.

Hence, option C is correct

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3 years ago