Question

Find the distance between the two points rounding to the nearest tenth (if necessary).

Answer 1

Answer:

$\boxed {\boxed {\sf d\approx 4.2}}$

Step-by-step explanation:

The formula for distance is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y) and (x₂, y₂) are the points.

We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:

• x₁= -6
• y₁ = 6
• x₂ = -3
• y₂ = 3

Substitute the values into the formula.

$d= \sqrt{ (-3 - -6)^2+(3-6)^2$

Solve inside the parentheses.

• -3 --6 = -3+6 = 3
• 3-6 = -3

$d= \sqrt{(3)^2+ (-3)^2$

Solve the exponents.

• (3)²= 3*3= 9
• (-3)²= -3*-3 =9

$d= \sqrt{9+9$

Add.

$d= \sqrt18$

$d= 4.24264069$

Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.

$d \approx 4.2$

The distance between the two points is apprximately 4.2