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lisov135 [29]
3 years ago
8

If a=3/6 and b=-3/-5 find -3a+4b

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

Step-by-step explanation:

-3(3/6) + 4(3/5)

-3(1/2) + 4(3/5)

-3/2 + 12/5

-15/10 + 24/10

9/10

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(Refer to the attached image)​
gayaneshka [121]

Explanation:

Provided <u>2 length sides</u> and <u>one angle</u> also need to find <u>one missing side</u>.

So, use cosine rule:

a² = b² + c² - 2bc cos(A)

<h3><u>Part 1</u></h3>

c² = 9² + 11² - 2(11)(9) cos(57)

c² = 94.16147

c = √94.16147 = 9.70 cm

<h3><u>Part 2</u></h3>

d² = 5² + 7² - 2(5)(7) cos(48)

d² = 27.16

d = √27.16 = 5.21

<h3><u>Part 3</u></h3>

5² = 7² + 9² - 2(7)(9) cos(H)

-126cos(H) = 25 - 49 - 81

cos(H) = -105/-126

cos(H) = 5/6

H = cos⁻¹(5/6) = 33.56°

<h3><u>Part 4</u></h3>

8² = 4² + 7² - 2(4)(7) cos(J)

-56cos(J) = 64 - 16 - 49

cos(J) = -1/-56

J = cos⁻¹(1/56) = 88.98°

Passcode: 3142

8 0
2 years ago
Solve the system of linear equations by substituting. Check your solution
Ghella [55]
QUESTION 4

The given system of linear equations are,

y = 5x - 7...(1)

and

- 3x - 2y = - 12...(2)

We put equation (1) into equation (2) to obtain,

- 3x - 2(5x - 7) = - 12

We expand to get,

- 3x - 10x + 14 = - 12

Group like terms to get,

- 3x - 10x = - 12 - 14

Simplify to get,

- 13x = - 26

Divide both sides by -13 to get,

x = 2

Put the value of x into equation (1) to get,

y = 5(2) - 7

y = 10 - 7 = 3

The solution is

x = 2 \: \: and \: \: = 3

QUESTION 5

The given system of linear equations are

-4x+y=6....(1)
and

-5x-y=21...(2)

We make y the subject in equation (1) to get,

y = 4x + 6....(3)

Put equation (3) into equation (2) to get,

- 5x - (4x + 6) = 21

We expand to get,

- 5x - 4x - 6 =21

We group like terms to get,

- 5x - 4x = 21 + 6

This implies that,

- 9x = 27

We divide both sides by -9 to get,

x = - 3

Put the value of x in to equation 3 to get,

y = 4( - 3) + 6

y = - 12 + 6 = - 6

Therefore the solution is

x = - 3 \: and \: y = - 6

QUESTION 6

The given equations are,

-7x-2y=-13...(1)

and

x-2y=-13...(2)

Make x the subject in equation (2) to get,

x = 2y - 13...(3)

Put equation (3) into equation (1) to get,
- 7(2y - 13) - 2y = - 13

We expand to get,

- 14y + 91 - 2y = - 13

We group like terms to obtain,

- 14y - 2y = - 13 - 91

.Simplify to get,

- 16y = - 104

Divide through by -16 to get,

y = \frac{13}{2}

Put the value of y into equation (3) to get,

x = 2( \frac{13}{2} ) - 13

x = 13 - 13 = 0

Therefore

x = 0 \: and \: y = \frac{13}{2}
8 0
3 years ago
Write the polynomial as a product: p^2q+r^2–pqr–pr<br> Thanks so much! Love you all who help!
Anarel [89]
Factor the equation so... 
(r^2-pr) and (p^2q-pqr)

Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)

Add a negative to r(r-p) to make it -r(p-r)

(pq-r)(p-r) is the answer...  I'm sorry I can't explain things well, but I tried.
5 0
3 years ago
Rita's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $55 a day for fo
MArishka [77]
<span>"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels m miles and is on a trip for x days then Rita will receive:

55x + 0.45m dollars. 


Rita drove 300 miles, means that m=300. Thus </span>55x + 0.45m becomes <span>

</span>55x+0.45m=55x+0.45 \cdot 300=55x+135 (dollars.)

She was reimbursed  $2,335 means that 55x+135=2,335.


Part A: 55x+135=2,335.

Part B: 

We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:

55x=2,335-135=2,200.

Dividing both sides by 55, we get: x=2,200/55=40.


Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip. 
5 0
4 years ago
Julien threw x number of pitches at baseball practice. Jacob threw 1/5 fewer than that
Naily [24]

Answer:

ok so jacob threw 1/5 of x

Step-by-step explanation:

if you say julien threw x and jacob threw 1/5 of that than jacob threw 1/5 of x

5 0
3 years ago
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