The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

Answer:
rachel is 10
Step-by-step explanation:
45/3=15
15-5=10
Answer:
So for the first one the first ting u have to do is FLIP the equation so---> X-12=y
Then you have to add 12 to BOTH sides----> x-12+12=y+12
<u><em>So your answer for X ----> x=y+12</em></u>
<u><em>For Y on the first equation it is--->y=x-12</em></u> (Just flipped and the sign changed)
For the second equation we are gonna solve for Y first.
The first thing u want to do is divide both sides by -3 so it will look like this
-3y/-3 = 2x/+36/-3
<u><em>So Y will equal-----> -2/3x- 12</em></u>
Now we are going to do the X part
So fist FLIP the equation----> 2x+36= -3y
The add -36 to both sides-----> 2x+36+-36=-3y+-36
Last step you have to divide both sides by 2
So that would be----> 2x/2= -3y-3
<u><em>Your final result will be----> x=-3/2y-18</em></u>
I hope this helped you out (:::::::
33x - 38/x^2 - 3x + 1
Hope this helps
a. We can parameterize
by


with
. Then

b. We can parameterize the opposite direction by instead setting


with
. Then

which gives the same value as in part (a).