So he's mixing:
1 gallon 2 quarts 3 pints of orange juice
1 gallon 3 quarts 7 pints of pineapple juice and
1 gallon 3
<span>
quarts 3 pints of ginger ale
that's:
3 gallons 8 quarts and 13 pints.
2 pints make a quart, so 13 pints make 6 quarts and 1 pint, so actually it's:
</span><span>3 gallons 8+6=14 quarts and 1 pint.
4 quarts are a gallon, and 14 quarts are 3 gallons 2 quarts, so the final answer is:
</span>
<span>3+3=6 gallons 2 quarts and 1 pint. </span>
By doing by over 2 it will equal yeah
Answer:
D h(x) = f(x)×g(x)
Step-by-step explanation:
h(x) has a wave with 2 changes in direction.
so, this needs to be an expression of the third degree (there must be a term with x³ as the highest power of x).
and that is only possible when multiplying both basic functions. all the other options would keep it at second degree (x²) or render it even to a first degree (linear).
Answer:
The coefficient is equal to
Step-by-step explanation:
we have
we know that
The coefficient is equal to
so
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation .
In this problem:
- The mean is of 660, hence .
- The standard deviation is of 90, hence .
- A sample of 100 is taken, hence .
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:
By the Central Limit Theorem
has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213