<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
Answer:
IS THERE MORE TO THE PROBLEM? NOT ENOUGH INFORMATION IS GIVEN
Step-by-step explanation:
Answer:
360 degrees in total.
Step-by-step explanation:
We are given that the m∠1 is 145 degrees, and because ∠1 and ∠2 form a straight line we can tell that 180-145 = 35.
So now here's what we know:
m∠1 = 145
m∠2 = 35
After that, we need to look at ∠5 and ∠6.
One thing we can notice right away is that ∠5 and ∠6 should measure the same as ∠1 and ∠2 (respectively) because they are corresponding angles.
Now we will add them all together to find the sum of all four angles.
m∠1 = 145 + m∠2 = 35 = 180
m∠5= 145 + m∠6 = 35 = 180
180 + 180 = 360
Answer:
a^3 - b^3.
Step-by-step explanation:
Area = length * breadth
= (a - b)(a^2 + ab + b^2)
= a(a^2 + ab + b^2) - b(a^2 + ab + b^2)
= a^3 + a^2b + ab^2 - a^2b - ab^2 - b^3
Note: the 4 middle terms cancel out. So the answer is
a^3 - b^3.